F(-1)=3x^2+16

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Solution for F(-1)=3x^2+16 equation: 



(-1)=3F^2+16

We move all terms to the left:

(-1)-(3F^2+16)=0

We add all the numbers together, and all the variables

-(3F^2+16)-1=0

We get rid of parentheses

-3F^2-16-1=0

We add all the numbers together, and all the variables

-3F^2-17=0

a = -3; b = 0; c = -17;
Δ = b2-4ac
Δ = 02-4·(-3)·(-17)
Δ = -204
Delta is less than zero, so there is no solution for the equation

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